BF2S Forums College/University Homework Help Thread v2.0

Can someone help me find the expected annual cash flow to shareholders for this company F5 Technologies http://finance.yahoo.com/q?s=FFIV

I need it for a Discounted Cash Flow Valuation for a presentation I'm doing on the company to my school's board of trustees.

Ryan wrote:

Well, since I regarded that thread as being beneficial to myself, I think a new one should be created focussing only on the issue of answering other peoples homework questions or guiding them to a solution and not arguing over which uni/college is better, etc.

I usually go to Yahoo Answers to ask/find help to a question I'm stumped on, but I come here too to seek help and help other members with their homework problems.

If you're having issues with calc, I suggest you look up videos by PatrickJMT on youtube. The guy breaks down difficult stuff and teaches you more in five minutes than I got from my professors lectures.

Hurricane2k9 wrote:

need to write a dissertation on the heat death of the universe by tomorrow +1 for help

You should read The Last Question by Isaac Asimov.

Full text can be found here:

http://www.multivax.com/last_question.html


Please note, the above is complete fiction and should not be taken in anyway seriously or used for acadamia purposes. I mean, honestly - that ending? Child, please.

lol i was just about to reply the same thing. a dissertation is a piece of work that clocks in normally at 15,000 words (for arts and humanities undergrads - scientists obviously have a lower word-limit). a PhD candidate can expect to write a piece of work from 30,000-50,000 words, typically (though there is no word limit for a PhD). my undergraduate thesis was 10,000 words and barely earned the 'dissertation' title. what can you possibly be writing overnight? it barely qualifies as an essay if it's < 2,500 words, imo. otherwise it's just a short assignment for a class. lol.

so it's a 500 word précis you're being asked to do then

Superior Mind wrote:

Do you think I would get away with creating an original porno as a visual anthropology project? We have seven minutes to present anything that relates to 'escapism.'

Pretty sure that's already been done.

Search youtube for "I have the weirdest boner right now"

Jay wrote:

Ryan wrote:

Well, since I regarded that thread as being beneficial to myself, I think a new one should be created focussing only on the issue of answering other peoples homework questions or guiding them to a solution and not arguing over which uni/college is better, etc.

I usually go to Yahoo Answers to ask/find help to a question I'm stumped on, but I come here too to seek help and help other members with their homework problems.

If you're having issues with calc, I suggest you look up videos by PatrickJMT on youtube. The guy breaks down difficult stuff and teaches you more in five minutes than I got from my professors lectures.

Yea man I've watched his videos in the past, they are very helpful. Chemguy also has great videos for chemistry. I have a physics problem though. It seems so easy, but I'm stumped:

a projectile of mass 2.0kg approaches a stationary target body at 5.0m/s. The projectile is deflected through 60 degrees and its speed after the collision is 3m/s. What is the magnitude of the momentum of the target body after the collision?

Yea, wouldn't it be

(Mb)(vb)i + (Mt)(vt)i = (Mb)(vb)f + (Mt)(vt)f

Where Mb is the mass of the bullet, Mw mass of target, vb velocity of bullet, vt velocity of target

velocity of the target initial is 0, so I can cancel out (Mt)(vt)i
I'm solving for (Mt)(vt)f, which would be (Mb)(vb)i - (Mb)(vb)f

Lemme try something... lol

Agh, too hard trying to do it on a computer. I'll get it eventually.

Last edited by Ryan (2011-11-22 16:49:26)

unnamednewbie13 wrote:

Learn excel and plug your formulas into it if you want to see them solved in real time.

Not very useful when he needs to know how to do it by hand for the test.

I suck at excel. I figured it out with my noggin'

Sure, as long as you tell it to.

This is how they calculated:
Molar mass of lithium: M=6,941 g/mol
Density of solid lithium: 515 kg/m^3 = 515000 g/m^3 = 74196,8 mol/m^3 = 1,3477*10^-5 m^3/mol --> this is the volume of 1 mol lithium
1,57% volume change: (1,3477*10^-5)*1,0157 = 1,3689*10^-5 m^3
dV=(1,3689-1,3477)*10^-5 = 2,12*10^-7 m^3

Now, we have this equation here:

dT/dp = (Tm*dV)/dfH
Where dT is the change of the melting point in Kelvin, dp is the change of pressure in Pascal, Tm is the standard melting point, dV is the change of volume in m^3, and dfH is the enthalpy of fusion in Joule/mol.
So you have every data you need to find dT.
dp=1,01223*10^8 Pa
Tm=453,69 K
dV= 2,12*10^-7 m^3
dfH= 3024 Joule/mol

So dT=3,2195 K , which means that the new melting point (at 1000 atm) is 456,9 K